牛客周赛 Round 50

A

模拟一下

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#include<bits/stdc++.h>
using namespace std;
int main()
{
    int a,b,x;
    cin>>a>>b>>x;
    if(min(a,b)+x>max(a,b))
    {
        cout<<"YES";
    }
    else
    {
cout<<"NO";}
}

B

讨论一下1的情况

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#include<bits/stdc++.h>
using namespace std;
int a[4];
int main()
{
    for(int i=1;i<=3;i++)
    {
        cin>>a[i];
    }
    sort(a+1,a+1+3);
    if(a[1]==1)
    {
        if(a[2]==1)
        {
            if(a[3]==1)
            {
                cout<<3;
            }
            else
            {
                cout<<max(a[3]*2,a[3]+2);
            }
        }
        else
        {
            cout<<max((a[1]+a[2])*a[3],(a[1]+a[3])*a[2]);
        }
    }
    else
    {
        cout<<max(a[3]*a[2]*a[1],max((a[1]+a[2])*a[3],max((a[1]+a[3])*a[2],(a[3]+a[2])*a[1])));
    }
}

C

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#include<bits/stdc++.h>
using namespace std;
int main()
{
    int a,b,c;
    cin>>a>>b>>c;
    int x=a*b*c;
    int y=(a+b)*c;
    int z=a*(b+c);
    int g=a+b+c;
    cout<<max(x,max(y,max(z,g)));
}

也许是我B写复杂了，C很快就结束了

D

枚举一下因子即可

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#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
void solve()
{
    
        ll a,b,c;
        cin>>a>>b>>c;
        vector<ll> x;
        x.clear();
        if(c==0)
        {
            cout<<a<<" "<<b<<" "<<1<<" "<<0<<endl;
            
            return;
        }
            for(ll i=1;i<=abs(a);i++)
            {
                if(a%i==0)
                {
                    
                    x.push_back(i);
                    x.push_back(-i);
                    x.push_back(a/i);
                    x.push_back(-(a/i));
                }
            }
            
        
        
        vector<ll> y;
        y.clear();
        for(ll i=1;i<=abs(c);i++)
            {
                if(c%i==0)
                {
                   
                    y.push_back(i);
                    y.push_back(-i);
                    y.push_back(c/i);
                    y.push_back(-(c/i));
                }
            }
        
        
        for(int i=0;i<x.size();i++)
        {
            for(int j=0;j<y.size();j++)
            {
                
                if(x[i]*y[j]+c/y[j]*a/x[i]==b)
                {
                    cout<<x[i]<<" "<<c/y[j]<<" "<<a/x[i]<<" "<<y[j]<<endl;
                    return;
                }
                
            }
        }
        
        cout<<"NO"<<endl;
       
    
}
int main()
{
    int t;
    cin>>t;
    while(t--)
    {
        solve();
    }
}